chemistry test\nunit #01 - scientific measurement & matter\nname: kaleb jakomino\nperiod: a3 date…

chemistry test\nunit #01 - scientific measurement & matter\nname: kaleb jakomino\nperiod: a3 date: 15/9/25\npart a = fill in the blank\nwrite the word that correctly answers each blank.\nwhen measuring in science, a defined unit based on an object or event in the physical world is called a(n) __1__. the three most common units discussed in the book are the __2__, __3__, and __4__, which measure length, time, and mass respectively. one of the most important useful measurements in chemistry is density which is the ratio of the __5__ of an object to the __6__ of the same object. the base unit of temperature is a __7__. when changing between units of measurement, a ratio of __8__ values known as a conversion factor is used to change the unit, but not the value of the measurement. whether to multiply or divide is determined by using the units, which is known as __9__.\nwhen evaluating your data, how close your measurements are to each other is called your __10__, while how close your measurement is to the actual value is called your __11__. the calculation of how right or wrong data is is known as the __12__.\nwhen graphing data collected, there are three main types of graphs you can use. if your data has two sets of numerical data, you should use a __13__ graph, where parts of a whole should be placed on a __14__ graph, and a single quantity being compared with multiple factors goes on a __15__ graph.\npart b = measurements & calculations\nanswer each of the following.\n(8) perform each of the following operations using the measurements provided.\n(2) add: 3x10^9 m + 5x10^10 m\n(2) subtract: 5.01x10^-7 s - 30x10^-9 s\n(2) multiply: 8 in x 8 in\n(2) divide: 342 cm^3 / 21 cm\nhow many meters are there in 5.1 km?\n(3) how many seconds are in 105 picoseconds?

chemistry test\nunit #01 - scientific measurement & matter\nname: kaleb jakomino\nperiod: a3 date: 15/9/25\npart a = fill in the blank\nwrite the word that correctly answers each blank.\nwhen measuring in science, a defined unit based on an object or event in the physical world is called a(n) __1__. the three most common units discussed in the book are the __2__, __3__, and __4__, which measure length, time, and mass respectively. one of the most important useful measurements in chemistry is density which is the ratio of the __5__ of an object to the __6__ of the same object. the base unit of temperature is a __7__. when changing between units of measurement, a ratio of __8__ values known as a conversion factor is used to change the unit, but not the value of the measurement. whether to multiply or divide is determined by using the units, which is known as __9__.\nwhen evaluating your data, how close your measurements are to each other is called your __10__, while how close your measurement is to the actual value is called your __11__. the calculation of how right or wrong data is is known as the __12__.\nwhen graphing data collected, there are three main types of graphs you can use. if your data has two sets of numerical data, you should use a __13__ graph, where parts of a whole should be placed on a __14__ graph, and a single quantity being compared with multiple factors goes on a __15__ graph.\npart b = measurements & calculations\nanswer each of the following.\n(8) perform each of the following operations using the measurements provided.\n(2) add: 3x10^9 m + 5x10^10 m\n(2) subtract: 5.01x10^-7 s - 30x10^-9 s\n(2) multiply: 8 in x 8 in\n(2) divide: 342 cm^3 / 21 cm\nhow many meters are there in 5.1 km?\n(3) how many seconds are in 105 picoseconds?

Answer

Explanation:

Step1: Add the scientific - notation values

First, rewrite $3\times10^{9}\text{ m}$ and $5\times10^{10}\text{ m}$ with the same exponent. $3\times10^{9}\text{ m}=0.3\times 10^{10}\text{ m}$. Then $(0.3\times10^{10}+5\times10^{10})\text{ m}=(0.3 + 5)\times10^{10}\text{ m}=5.3\times10^{10}\text{ m}$.

Step2: Subtract the scientific - notation values

Rewrite $30\times10^{-9}\text{ s}=0.3\times10^{-7}\text{ s}$. Then $(5.01\times10^{-7}-0.3\times10^{-7})\text{ s}=(5.01 - 0.3)\times10^{-7}\text{ s}=4.71\times10^{-7}\text{ s}$.

Step3: Multiply the values

$8\text{ in}\times8\text{ in}=64\text{ in}^2$.

Step4: Divide the values

$342\text{ cm}^3\div21\text{ cm}=\frac{342}{21}\text{ cm}^2 = 16.29\text{ cm}^2$ (rounded to two decimal places).

Step5: Convert kilometers to meters

Since $1\text{ km}=1000\text{ m}$, then $5.1\text{ km}=5.1\times1000\text{ m}=5100\text{ m}$.

Step6: Convert picoseconds to seconds

Since $1\text{ ps}=10^{-12}\text{ s}$, then $105\text{ ps}=105\times10^{-12}\text{ s}=1.05\times10^{-10}\text{ s}$.

Answer:

a. $5.3\times10^{10}\text{ m}$ b. $4.71\times10^{-7}\text{ s}$ c. $64\text{ in}^2$ d. $16.29\text{ cm}^2$ 5100 m $1.05\times10^{-10}\text{ s}$