c. cl₂(g) + mgbr₂(aq) → mgcl₂(aq) + br₂(aq)\nd. cu(s) + ag₂co₃(s) → cuco₃(s) + ag(s)\ne. br₂(g) + ki(aq) →…

c. cl₂(g) + mgbr₂(aq) → mgcl₂(aq) + br₂(aq)\nd. cu(s) + ag₂co₃(s) → cuco₃(s) + ag(s)\ne. br₂(g) + ki(aq) → i₂(aq) + kbr(aq)\n4) balance each equation for a double replacement reaction.\na. na₂so₄(aq) + bacl₂(aq) → baso₄(s) + nacl(aq)\nb. hno₃(aq) + ba(oh)₂(aq) → hoh(l) + ba(no₃)₂(aq)\nc. na₂co₃(aq) + fe(no₃)₃(aq) → fe₂(co₃)₃(s) + nano₃(aq)\nd. cacl₂(aq) + k₃po₄(aq) → ca₃(po₄)₂(s) + kcl(aq)\ne. naoh(aq) + h₂so₄(aq) → h₂o(l) + na₂so₄(aq)

c. cl₂(g) + mgbr₂(aq) → mgcl₂(aq) + br₂(aq)\nd. cu(s) + ag₂co₃(s) → cuco₃(s) + ag(s)\ne. br₂(g) + ki(aq) → i₂(aq) + kbr(aq)\n4) balance each equation for a double replacement reaction.\na. na₂so₄(aq) + bacl₂(aq) → baso₄(s) + nacl(aq)\nb. hno₃(aq) + ba(oh)₂(aq) → hoh(l) + ba(no₃)₂(aq)\nc. na₂co₃(aq) + fe(no₃)₃(aq) → fe₂(co₃)₃(s) + nano₃(aq)\nd. cacl₂(aq) + k₃po₄(aq) → ca₃(po₄)₂(s) + kcl(aq)\ne. naoh(aq) + h₂so₄(aq) → h₂o(l) + na₂so₄(aq)

Answer

Explanation:

Step1: Balance sodium and chlorine in a

There are 2 sodium atoms in $Na_2SO_4$ and 1 in $NaCl$, and 2 chlorine atoms in $BaCl_2$ and 1 in $NaCl$. Add a coefficient of 2 to $NaCl$. $Na_2SO_4(aq)+BaCl_2(aq)\rightarrow BaSO_4(s)+2NaCl(aq)$

Step2: Balance hydrogen and nitrate in b

There are 1 hydrogen atom in $HNO_3$ and 2 in $HOH$ (i.e., $H_2O$), and 2 nitrate groups in $Ba(NO_3)_2$ and 1 in $HNO_3$. Add a coefficient of 2 to $HNO_3$ and 2 to $H_2O$. $2HNO_3(aq)+Ba(OH)_2(aq)\rightarrow 2H_2O(l)+Ba(NO_3)_2(aq)$

Step3: Balance sodium, iron and nitrate in c

There are 2 sodium atoms in $Na_2CO_3$ and 1 in $NaNO_3$, 1 iron atom in $Fe(NO_3)_3$ and 2 in $Fe_2(CO_3)_3$. Add a coefficient of 3 to $Na_2CO_3$, 2 to $Fe(NO_3)_3$ and 6 to $NaNO_3$. $3Na_2CO_3(aq)+2Fe(NO_3)_3(aq)\rightarrow Fe_2(CO_3)_3(s)+6NaNO_3(aq)$

Step4: Balance calcium, potassium, phosphorus and chlorine in d

There are 3 calcium atoms in $Ca_3(PO_4)_2$ and 1 in $CaCl_2$, 3 potassium atoms in $K_3PO_4$ and 1 in $KCl$. Add a coefficient of 3 to $CaCl_2$, 2 to $K_3PO_4$ and 6 to $KCl$. $3CaCl_2(aq)+2K_3PO_4(aq)\rightarrow Ca_3(PO_4)_2(s)+6KCl(aq)$

Step5: Balance sodium, hydrogen, sulfur and oxygen in e

There are 2 sodium atoms in $Na_2SO_4$ and 1 in $NaOH$, 2 hydrogen atoms in $H_2SO_4$ and 1 in $H_2O$. Add a coefficient of 2 to $NaOH$ and 2 to $H_2O$. $2NaOH(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+Na_2SO_4(aq)$

Answer:

a. $Na_2SO_4(aq)+BaCl_2(aq)\rightarrow BaSO_4(s)+2NaCl(aq)$ b. $2HNO_3(aq)+Ba(OH)_2(aq)\rightarrow 2H_2O(l)+Ba(NO_3)_2(aq)$ c. $3Na_2CO_3(aq)+2Fe(NO_3)_3(aq)\rightarrow Fe_2(CO_3)_3(s)+6NaNO_3(aq)$ d. $3CaCl_2(aq)+2K_3PO_4(aq)\rightarrow Ca_3(PO_4)_2(s)+6KCl(aq)$ e. $2NaOH(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+Na_2SO_4(aq)$