click the link here to open the atom - building interactive, and click the atom square. use the interactive…

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)? done

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)? done

Answer

Explanation:

Step1: Recall atomic - number concept for He

The atomic number of He is 2. In a neutral atom, the number of protons equals the atomic number. For a He atom with mass - number 4, the number of protons is 2.

Step2: Recall electron - configuration for Li

The atomic number of Li is 3. Its electron - configuration is 2, 1. For a Li atom with mass - number 7, the number of electrons in the outermost orbital is 1.

Step3: Calculate neutrons in N

The atomic number of N is 7. The mass - number is 14. The number of neutrons = mass - number−atomic number. So, the number of neutrons in a N atom with mass - number 14 is (14 - 7=7).

Step4: Recall electron - configuration for B

The atomic number of B is 5. Its electron - configuration is 2, 3. For a B atom with mass - number 11, the number of electrons in the second orbital is 3.

Answer:

  1. 2
  2. 1
  3. 7
  4. 3