click the link here to open the atom - building interactive, and click the atom square. use the interactive…

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)?

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)?

Answer

Explanation:

Step1: Recall atomic number concept for He

The atomic number of Helium (He) is 2. In a neutral atom, the number of protons equals the atomic number. So for a He - atom with mass number 4, the number of protons in the nucleus is 2.

Step2: Recall atomic number and electron - shell rules for Li

The atomic number of Lithium (Li) is 3. In a neutral atom, the number of electrons equals the number of protons. The electron - shell filling order is 2 in the first shell and the remaining in the second shell. So for Li with atomic number 3, the number of electrons in the outermost orbital is 1.

Step3: Recall mass - number formula for N

The mass number (A) is the sum of protons (p) and neutrons (n), i.e., $A=p + n$. The atomic number of Nitrogen (N) is 7. Given mass number $A = 14$, then $n=A - p=14 - 7 = 7$.

Step4: Recall atomic number and electron - shell rules for B

The atomic number of Boron (B) is 5. In a neutral atom, the number of electrons is 5. The first shell can hold 2 electrons, and the remaining $5 - 2=3$ electrons go to the second shell.

Answer:

  1. 2
  2. 1
  3. 7
  4. 3