co + 3h₂ → h₂o + ch₄\nhow many grams of methane, ch₄, are produced from the complete reaction of 3.75 moles…

Explanation:

Step1: Determine mole - ratio

From the balanced equation $CO + 3H_2\rightarrow H_2O+CH_4$, the mole - ratio of $H_2$ to $CH_4$ is 3:1.

Step2: Calculate moles of $CH_4$

Let $n_{CH_4}$ be the moles of $CH_4$ and $n_{H_2}$ be the moles of $H_2$. Using the mole - ratio, $n_{CH_4}=\frac{1}{3}n_{H_2}$. Given $n_{H_2} = 3.75$ moles, so $n_{CH_4}=\frac{1}{3}\times3.75 = 1.25$ moles.

Step3: Calculate mass of $CH_4$

We know that mass $m = n\times M$, where $n$ is the number of moles and $M$ is the molar mass. Given $M_{CH_4}=16.05$ g/mol and $n_{CH_4} = 1.25$ moles. So $m_{CH_4}=n_{CH_4}\times M_{CH_4}=1.25\times16.05 = 20.0625$ g.

Answer:

20.0625 g