what are the coefficients for the reaction _cl₂o₅ + _h₂o → _hclo₃ once it is balanced?\n1, 1, 1\n1, 1, 2\n1…

what are the coefficients for the reaction _cl₂o₅ + _h₂o → _hclo₃ once it is balanced?\n1, 1, 1\n1, 1, 2\n1, 2, 2\n2, 1, 1

what are the coefficients for the reaction _cl₂o₅ + _h₂o → _hclo₃ once it is balanced?\n1, 1, 1\n1, 1, 2\n1, 2, 2\n2, 1, 1

Answer

Explanation:

Step1: Balance chlorine atoms

On the left - hand side, in $\mathrm{Cl}{2}\mathrm{O}{5}$, there are 2 chlorine atoms. In $\mathrm{HClO}{3}$ on the right - hand side, there is 1 chlorine atom. To balance the chlorine atoms, if we put a coefficient of 2 in front of $\mathrm{HClO}{3}$, we have 2 chlorine atoms on both sides. The equation becomes $\mathrm{Cl}{2}\mathrm{O}{5}+\mathrm{H}{2}\mathrm{O}\to2\mathrm{HClO}{3}$.

Step2: Balance oxygen and hydrogen atoms

On the left - hand side, in $\mathrm{Cl}{2}\mathrm{O}{5}$, there are 5 oxygen atoms and in $\mathrm{H}{2}\mathrm{O}$ there is 1 oxygen atom, so a total of $5 + 1=6$ oxygen atoms. In $2\mathrm{HClO}{3}$, there are $2\times3 = 6$ oxygen atoms. Also, in $\mathrm{H}{2}\mathrm{O}$ there are 2 hydrogen atoms and in $2\mathrm{HClO}{3}$ there are 2 hydrogen atoms. So the balanced equation is $\mathrm{Cl}{2}\mathrm{O}{5}+\mathrm{H}{2}\mathrm{O}=2\mathrm{HClO}{3}$, and the coefficients are 1, 1, 2.

Answer:

1, 1, 2