what are the coefficients for the reaction _cl₂o₅ + _h₂o → _hclo₃ once it is balanced?\no 1,1,1\no 1,1,2\no…

Explanation:

Step1: Write the un - balanced equation

$Cl_2O_5 + H_2O\rightarrow HClO_3$

Step2: Balance the chlorine atoms

On the left - hand side, there are 2 chlorine atoms in $Cl_2O_5$. So, we put a 2 in front of $HClO_3$ on the right - hand side: $Cl_2O_5 + H_2O\rightarrow 2HClO_3$

Step3: Balance the hydrogen and oxygen atoms

Now, on the left - hand side, we have 2 hydrogen atoms in $H_2O$ and 6 oxygen atoms in $Cl_2O_5$ and 1 oxygen atom in $H_2O$ (total 7 oxygen atoms). On the right - hand side, in $2HClO_3$, we have 2 hydrogen atoms and 6 oxygen atoms. The equation is balanced as it is. The balanced equation is $Cl_2O_5 + H_2O = 2HClO_3$. The coefficients are 1, 1, 2.

Answer:

1, 1, 2