the combustion of glucose, c6h12o6(s), produces carbon dioxide, co2(g), and water, h2o(g), according to the…

the combustion of glucose, c6h12o6(s), produces carbon dioxide, co2(g), and water, h2o(g), according to the equation below. c6h12o6(s) + 6o2(g)→6co2(g) + 6h2o(l) the enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose? -2,840 kj/mol -473.3 kj/mol 473.3 kj/mol 2,840 kj/mol

the combustion of glucose, c6h12o6(s), produces carbon dioxide, co2(g), and water, h2o(g), according to the equation below. c6h12o6(s) + 6o2(g)→6co2(g) + 6h2o(l) the enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose? -2,840 kj/mol -473.3 kj/mol 473.3 kj/mol 2,840 kj/mol

Answer

Explanation:

Step1: Understand heat - of - combustion definition

The heat of combustion is the enthalpy change for the combustion of 1 mole of a substance.

Step2: Analyze the given reaction

The given reaction shows the combustion of 1 mole of glucose ($C_6H_{12}O_6$) with an enthalpy change of $\Delta H=- 2840\ kJ$.

Answer:

-2,840 kJ/mol