the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the…

the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the equation below.\nc₆h₁₂o₆(s) + 6o₂(g)→6co₂(g) + 6h₂o(l)\nthe enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose?\n-2,840 kj/mol\n-473.3 kj/mol\n473.3 kj/mol\n2,840 kj/mol

the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the equation below.\nc₆h₁₂o₆(s) + 6o₂(g)→6co₂(g) + 6h₂o(l)\nthe enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose?\n-2,840 kj/mol\n-473.3 kj/mol\n473.3 kj/mol\n2,840 kj/mol

Answer

Explanation:

Step1: Understand heat - of - combustion definition

The heat of combustion is the enthalpy change for the combustion of one mole of a substance.

Step2: Analyze given reaction

The given reaction is $\mathrm{C}{6}\mathrm{H}{12}\mathrm{O}{6}(s)+6\mathrm{O}{2}(g)\rightarrow6\mathrm{CO}{2}(g) + 6\mathrm{H}{2}\mathrm{O}(l)$ with $\Delta H=- 2840\ \mathrm{kJ}$. Here, 1 mole of glucose is reacting.

Answer:

$-2840\ \mathrm{kJ/mol}$