the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the…

the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the equation below.\nc₆h₁₂o₆(s) + 6o₂(g) → 6co₂(g) + 6h₂o(l)\nthe enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose?\n-2,840 kj/mol\n-473.3 kj/mol\n473.3 kj/mol\n2,840 kj/mol

the combustion of glucose, c₆h₁₂o₆(s), produces carbon dioxide, co₂(g), and water, h₂o(g), according to the equation below.\nc₆h₁₂o₆(s) + 6o₂(g) → 6co₂(g) + 6h₂o(l)\nthe enthalpy of the reaction is -2,840 kj. what is the heat of combustion, per mole, of glucose?\n-2,840 kj/mol\n-473.3 kj/mol\n473.3 kj/mol\n2,840 kj/mol

Answer

Explanation:

Step1: Understand heat - of - combustion definition

Heat of combustion is the enthalpy change for the combustion of 1 mole of a substance.

Step2: Analyze the given reaction

The given reaction shows the combustion of 1 mole of $C_6H_{12}O_6$ with an enthalpy change of $\Delta H=- 2840\ kJ$.

Answer:

A. $-2840\ kJ/mol$