complete the data table: use these values: the atomic mass of al is 27.0 g/mole. the atomic mass of pb is…

complete the data table: use these values: the atomic mass of al is 27.0 g/mole. the atomic mass of pb is 207.2 g/mole. use two significant digits for your answers: mass of al wire before reaction = 3.96 g mass of al wire after reaction = 3.65 g mass of al lost = g moles of al lost = moles mass of pb + filter paper = 4.26 g mass of filter paper = 0.92 g mass of pb = g moles of pb formed = moles

complete the data table: use these values: the atomic mass of al is 27.0 g/mole. the atomic mass of pb is 207.2 g/mole. use two significant digits for your answers: mass of al wire before reaction = 3.96 g mass of al wire after reaction = 3.65 g mass of al lost = g moles of al lost = moles mass of pb + filter paper = 4.26 g mass of filter paper = 0.92 g mass of pb = g moles of pb formed = moles

Answer

Answer:

Mass of Al lost: 0.31 g Moles of Al lost: 0.011 moles Mass of Pb: 3.34 g Moles of Pb formed: 0.016 moles

Explanation:

Step1: Calculate mass of Al lost

Subtract mass after from mass before. $3.96 - 3.65=0.31$ g

Step2: Calculate moles of Al lost

Use formula $n=\frac{m}{M}$, where $m = 0.31$ g and $M = 27.0$ g/mole. $n=\frac{0.31}{27.0}\approx0.011$ moles

Step3: Calculate mass of Pb

Subtract mass of filter - paper from mass of Pb + filter - paper. $4.26 - 0.92 = 3.34$ g

Step4: Calculate moles of Pb formed

Use formula $n=\frac{m}{M}$, where $m = 3.34$ g and $M = 207.2$ g/mole. $n=\frac{3.34}{207.2}\approx0.016$ moles