complete the following table to confirm correct lewis dot structure format. this is not the report sheet…

complete the following table to confirm correct lewis dot structure format. this is not the report sheet: formula name skeleton # of valence e⁻ e⁻ used in single bonds remaining electrons complete lewis structure ch₄ methane nh₃ nitrogen trihydride (ammonia) h₂s dihydrogen sulfide hocn cyanic acid h - o - c - n 16e⁻ 10e⁻ 6e⁻ h - ö - c ≡ n: bf₃ boron trifluoride

complete the following table to confirm correct lewis dot structure format. this is not the report sheet: formula name skeleton # of valence e⁻ e⁻ used in single bonds remaining electrons complete lewis structure ch₄ methane nh₃ nitrogen trihydride (ammonia) h₂s dihydrogen sulfide hocn cyanic acid h - o - c - n 16e⁻ 10e⁻ 6e⁻ h - ö - c ≡ n: bf₃ boron trifluoride

Answer

Explanation:

Step1: Determine valence electrons for CH₄

Carbon has 4 valence electrons and each hydrogen has 1. So total valence electrons = 4+(1×4)=8. Skeleton is C in the center with 4 H's around it. Number of single - bonds is 4, using 8 electrons (2 per bond), and remaining electrons is 0. Complete Lewis structure: H - C(4 H's around it with single bonds).

Step2: Determine valence electrons for NH₃

Nitrogen has 5 valence electrons and each hydrogen has 1. So total valence electrons = 5+(1×3)=8. Skeleton is N in the center with 3 H's around it. Number of single - bonds is 3, using 6 electrons (2 per bond), and remaining electrons is 2 (a lone pair on N). Complete Lewis structure: H - N(-H)(-H) with a lone pair on N.

Step3: Determine valence electrons for H₂S

Sulfur has 6 valence electrons and each hydrogen has 1. So total valence electrons = 6+(1×2)=8. Skeleton is S in the center with 2 H's around it. Number of single - bonds is 2, using 4 electrons (2 per bond), and remaining electrons is 4 (2 lone pairs on S). Complete Lewis structure: H - S(-H) with 2 lone pairs on S.

Step4: Determine valence electrons for BF₃

Boron has 3 valence electrons and each fluorine has 7. So total valence electrons = 3+(7×3)=24. Skeleton is B in the center with 3 F's around it. Number of single - bonds is 3, using 6 electrons (2 per bond), and remaining electrons is 18 (6 lone pairs, 3 on each F). Complete Lewis structure: F - B(-F)(-F) with 3 lone pairs on each F.

Formula Name Skeleton # of valence e⁻ e⁻ used in single bonds Remaining electrons Complete Lewis structure
CH₄ methane C surrounded by 4 H's 8 8 0 H - C(-H)(-H)(-H)(-H)
NH₃ nitrogen trihydride (ammonia) N surrounded by 3 H's 8 6 2 H - N(-H)(-H) with a lone pair on N
H₂S dihydrogen sulfide S surrounded by 2 H's 8 4 4 H - S(-H) with 2 lone pairs on S
HOCN cyanic acid H - O - C - N 16 10 6 H - O(-C≡N) with 2 lone pairs on O
BF₃ boron trifluoride B surrounded by 3 F's 24 6 18 F - B(-F)(-F) with 3 lone pairs on each F

Answer:

Formula Name Skeleton # of valence e⁻ e⁻ used in single bonds Remaining electrons Complete Lewis structure
CH₄ methane C surrounded by 4 H's 8 8 0 H - C(-H)(-H)(-H)(-H)
NH₃ nitrogen trihydride (ammonia) N surrounded by 3 H's 8 6 2 H - N(-H)(-H) with a lone pair on N
H₂S dihydrogen sulfide S surrounded by 2 H's 8 4 4 H - S(-H) with 2 lone pairs on S
HOCN cyanic acid H - O - C - N 16 10 6 H - O(-C≡N) with 2 lone pairs on O
BF₃ boron trifluoride B surrounded by 3 F's 24 6 18 F - B(-F)(-F) with 3 lone pairs on each F