2. what is the % composition of cl and in nacl?\n% composition = atomic mass of the component element x no…

2. what is the % composition of cl and in nacl?\n% composition = atomic mass of the component element x no. of atoms x 100% / molar mass of compound\n3. what is the % composition of cl and in kcl?\n% composition = atomic mass of the component element x no. of atoms x 100% / molar mass of compound\n4. which compound has higher % cl? why? kcl or nacl because
Answer
Explanation:
Step1: Calculate molar mass of NaCl
The atomic mass of Na is approximately 22.99 g/mol and Cl is approximately 35.45 g/mol. Molar mass of NaCl ($M_{NaCl}$) = 22.99 + 35.45=58.44 g/mol.
Step2: Calculate % composition of Cl in NaCl
Using the formula $%$ Composition = $\frac{\text{atomic mass of the component element}\times\text{No. of atoms}}{\text{Molar mass of compound}}\times100%$. For Cl in NaCl, $%$ Cl in NaCl = $\frac{35.45\times1}{58.44}\times100%\approx60.66%$.
Step3: Calculate molar mass of KCl
The atomic mass of K is approximately 39.10 g/mol and Cl is 35.45 g/mol. Molar mass of KCl ($M_{KCl}$)=39.10 + 35.45 = 74.55 g/mol.
Step4: Calculate % composition of Cl in KCl
Using the formula $%$ Composition = $\frac{\text{atomic mass of the component element}\times\text{No. of atoms}}{\text{Molar mass of compound}}\times100%$. For Cl in KCl, $%$ Cl in KCl=$\frac{35.45\times1}{74.55}\times100%\approx47.55%$.
Step5: Compare % composition of Cl in NaCl and KCl
Since 60.66%>47.55%, NaCl has a higher percentage - composition of Cl. The reason is that the molar mass of Na is less than that of K, and when calculating the percentage - composition of Cl, the denominator (molar mass of the compound) is smaller for NaCl while the numerator (atomic mass of Cl) is the same in both cases.
Answer:
- $%$ Cl in NaCl $\approx$ 60.66%
- $%$ Cl in KCl $\approx$ 47.55%
- NaCl has a higher % Cl because the molar mass of Na is less than that of K, resulting in a smaller molar - mass of NaCl compared to KCl while the atomic mass of Cl is the same in both compounds.