compound x has a molar mass of 416.41 g·mol⁻¹ and the following composition: element mass % phosphorus…

Explanation:

Step1: Calculate mass of each element in 1 - mole of compound

Assume we have 1 mole of compound (X) with a mass of (m = 416.41\ g). The mass of phosphorus ((P)) in 1 - mole of compound (X) is (m_P=416.41\ g\times0.1488 = 62.062\ g). The mass of chlorine ((Cl)) in 1 - mole of compound (X) is (m_{Cl}=416.41\ g\times0.8512 = 354.348\ g).

Step2: Calculate moles of each element

The molar mass of (P) is (M_P = 30.97\ g/mol), so the number of moles of (P), (n_P=\frac{m_P}{M_P}=\frac{62.062\ g}{30.97\ g/mol}=2\ mol). The molar mass of (Cl) is (M_{Cl}=35.45\ g/mol), so the number of moles of (Cl), (n_{Cl}=\frac{m_{Cl}}{M_{Cl}}=\frac{354.348\ g}{35.45\ g/mol}=10\ mol).

Answer:

(P_2Cl_{10})