a compound has a molecular weight of 112.124 atomic mass units and the empirical formula c₃h₄o. what is the…
a compound has a molecular weight of 112.124 atomic mass units and the empirical formula c₃h₄o. what is the molecular formula of the compound? use the periodic table to help you.\na. c₆h₈o\nb. c₉h₁₂o₃\nc. c₈h₄o₂\nd. c₄h₈o₂\ne. c₆h₈o₂
Answer
Answer:
E. $C_{6}H_{8}O_{2}$
Explanation:
Step1: Calculate empirical - formula weight
The atomic masses of $C = 12.01$ amu, $H = 1.008$ amu, and $O = 16.00$ amu. For $C_{3}H_{4}O$, the empirical - formula weight $M_{e}=3\times12.01 + 4\times1.008+1\times16.00=36.03 + 4.032 + 16.00 = 56.062$ amu.
Step2: Find the ratio $n$
$n=\frac{\text{Molecular weight}}{\text{Empirical - formula weight}}=\frac{112.124}{56.062}=2$.
Step3: Determine the molecular formula
Multiply the sub - scripts in the empirical formula by $n$. The molecular formula is $(C_{3}H_{4}O)\times2 = C_{6}H_{8}O_{2}$.