consider the balanced equation below.\n2h₂s + 3o₂ → 2so₂ + 2h₂o\nwhich option gives the correct mole…
consider the balanced equation below.\n2h₂s + 3o₂ → 2so₂ + 2h₂o\nwhich option gives the correct mole ratios?\no h₂s:so₂ = 2:2 and o₂:h₂o = 3:2\no h₂s:so₂ = 2:3 and o₂:h₂o = 3:2\no h₂s:so₂ = 4:4 and o₂:h₂o = 5:4\no h₂s:so₂ = 4:6 and o₂:h₂o = 4:4
Answer
Explanation:
Step1: Identify coefficients of reactants and products
For the reaction $2H_2S + 3O_2\rightarrow2SO_2+2H_2O$, the coefficient of $H_2S$ is 2, of $O_2$ is 3, of $SO_2$ is 2 and of $H_2O$ is 2.
Step2: Calculate mole - ratios
The mole - ratio of $H_2S$ to $SO_2$ is $\frac{\text{coefficient of }H_2S}{\text{coefficient of }SO_2}=\frac{2}{2}=2:2$. The mole - ratio of $O_2$ to $H_2O$ is $\frac{\text{coefficient of }O_2}{\text{coefficient of }H_2O}=\frac{3}{2}=3:2$.
Answer:
$H_2S:SO_2 = 2:2$ and $O_2:H_2O = 3:2$