consider the balanced equation.\ncuso₄ + zn → znso₄ + cu\nif 200.0 g of copper(ii) sulfate react with an…

Explanation:

Step1: Calculate molar mass of CuSO₄

The molar mass of CuSO₄: Cu (63.55 g/mol), S (32.07 g/mol), O (16.00 g/mol). So $M_{CuSO_4}=63.55 + 32.07+4\times16.00=159.62$ g/mol.

Step2: Calculate moles of CuSO₄

Given mass of CuSO₄ is $m = 200.0$ g. Using the formula $n=\frac{m}{M}$, we have $n_{CuSO_4}=\frac{200.0}{159.62}\approx1.253$ mol.

Step3: Determine mole - ratio from the balanced equation

From the balanced equation $CuSO_4+Zn\rightarrow ZnSO_4 + Cu$, the mole - ratio of $CuSO_4$ to $Cu$ is 1:1. So $n_{Cu}=n_{CuSO_4}\approx1.253$ mol.

Step4: Calculate mass of Cu

The molar mass of Cu is $M_{Cu}=63.55$ g/mol. Using the formula $m = n\times M$, we get $m_{Cu}=1.253\times63.55\approx79.63$ g.

Answer:

79.63 g