consider the equation for the formation of water.\n2h₂ + o₂ → 2h₂o\nwhat is the theoretical yield of h₂o if…

Explanation:

Step1: Calculate moles of $H_2$

The molar mass of $H_2$ is $M_{H_2}=2\ g/mol$. The number of moles of $H_2$, $n_{H_2}=\frac{m_{H_2}}{M_{H_2}}=\frac{18\ g}{2\ g/mol}=9\ mol$.

Step2: Determine moles of $H_2O$ from mole - ratio

From the balanced chemical equation $2H_2 + O_2\rightarrow2H_2O$, the mole - ratio of $H_2$ to $H_2O$ is 1:1. So, if $n_{H_2} = 9\ mol$, then $n_{H_2O}=9\ mol$.

Step3: Calculate theoretical mass of $H_2O$

The molar mass of $H_2O$ is $M_{H_2O}=(2\times1 + 16)\ g/mol = 18\ g/mol$. The theoretical mass of $H_2O$, $m_{H_2O}=n_{H_2O}\times M_{H_2O}=9\ mol\times18\ g/mol = 162\ g\approx160\ g$ (due to rounding in molar - mass values in common use).

Answer:

160 g