consider the equations below. (1) ca(s) + co2(g) + 1/2o2(g) → caco3(s) (2) 2ca(s)+o2(g) → 2cao(s) how should…

consider the equations below. (1) ca(s) + co2(g) + 1/2o2(g) → caco3(s) (2) 2ca(s)+o2(g) → 2cao(s) how should you manipulate these equations so that they produce the equation below when added? check all that apply. cao(s) + co2(g) → caco3(s) reverse the direction of equation (2) multiply equation (1) by 3 multiply equation (2) by 1/2 done
Answer
Explanation:
Step1: Analyze the target equation
We want to get $CaO(s)+CO_2(g)\to CaCO_3(s)$ from the given equations.
Step2: Analyze equation (2)
Equation (2) is $2Ca(s)+O_2(g)\to 2CaO(s)$. If we reverse it, we get $2CaO(s)\to 2Ca(s)+O_2(g)$. Dividing this reversed - equation by 2 gives $CaO(s)\to Ca(s)+\frac{1}{2}O_2(g)$.
Step3: Analyze equation (1)
Equation (1) is $Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\to CaCO_3(s)$.
Step4: Combine the manipulated equations
Adding the manipulated equation (2) ($CaO(s)\to Ca(s)+\frac{1}{2}O_2(g)$) and equation (1) ($Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\to CaCO_3(s)$) gives $CaO(s)+CO_2(g)\to CaCO_3(s)$.
Answer:
reverse the direction of equation (2), multiply equation (2) by 1/2