consider these equations.\nch₄(g) → c(s) + 2h₂(g) δh₁ = 74.6kj\nc(s) + 2cl₂(g) → ccl₄(g) δh₂ =…

consider these equations.\nch₄(g) → c(s) + 2h₂(g) δh₁ = 74.6kj\nc(s) + 2cl₂(g) → ccl₄(g) δh₂ = -95.7kj\n2h₂(g) + 2cl₂(g) → 4hcl(g) δh₃ = -184.6kj\nch₄(g) + 4cl₂(g) → ccl₄(g) + 4hcl(g) δh₄ = -206.7kj\ncomplete this based on the diagram.\narrow c\nhas a magnitude that is greater than that of b\nhas a magnitude that is less than that of b\nhas negative enthalpy

consider these equations.\nch₄(g) → c(s) + 2h₂(g) δh₁ = 74.6kj\nc(s) + 2cl₂(g) → ccl₄(g) δh₂ = -95.7kj\n2h₂(g) + 2cl₂(g) → 4hcl(g) δh₃ = -184.6kj\nch₄(g) + 4cl₂(g) → ccl₄(g) + 4hcl(g) δh₄ = -206.7kj\ncomplete this based on the diagram.\narrow c\nhas a magnitude that is greater than that of b\nhas a magnitude that is less than that of b\nhas negative enthalpy

Answer

Explanation:

Step1: Analyze the energy - level diagram

The diagram represents energy changes in a reaction - like process. The lengths of the arrows represent the magnitudes of energy changes.

Step2: Compare magnitudes of arrows

By visual inspection of the diagram, arrow C is shorter than arrow B. So the magnitude of the energy change represented by arrow C is less than that of arrow B.

Answer:

has a magnitude that is less than that of B