consider the following reversible reaction. 2h2o(g)⇌2h2(g)+o2(g) what is the equilibrium constant expression…

consider the following reversible reaction. 2h2o(g)⇌2h2(g)+o2(g) what is the equilibrium constant expression for the given system? o keq=h2o/h2o2 o keq=h2o^2/h2^2o2 o keq=h2^2o2/h2o o keq=h2^2o2/h2o^2

consider the following reversible reaction. 2h2o(g)⇌2h2(g)+o2(g) what is the equilibrium constant expression for the given system? o keq=h2o/h2o2 o keq=h2o^2/h2^2o2 o keq=h2^2o2/h2o o keq=h2^2o2/h2o^2

Answer

Answer:

The correct option is $\ce{K_{eq}}=\frac{[\ce{H2}]^2[\ce{O2}]}{[\ce{H2O}]^2}$ (the last - option which is not fully visible in your image but should be $\frac{[\ce{H2}]^2[\ce{O2}]}{[\ce{H2O}]^2}$ based on the rules of writing equilibrium constant expressions).

Explanation:

Step1: Recall equilibrium constant rule

For a reaction $aA + bB\rightleftharpoons cC + dD$, $\ce{K_{eq}}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$.

Step2: Identify reactants and products

In $2\ce{H2O}(g)\rightleftharpoons 2\ce{H2}(g)+\ce{O2}(g)$, reactant is $\ce{H2O}$ and products are $\ce{H2}$ and $\ce{O2}$.

Step3: Write the equilibrium - constant expression

$\ce{K_{eq}}=\frac{[\ce{H2}]^2[\ce{O2}]}{[\ce{H2O}]^2}$, where the exponents are the coefficients of the species in the balanced chemical equation.