consider the following reversible reaction. co(g) + 2h2(g) ⇌ ch3oh(g) what is the equilibrium constant…

Explanation:

Step1: Recall equilibrium - constant formula

For a general reaction $aA + bB\rightleftharpoons cC$, the equilibrium - constant expression $K_{eq}=\frac{[C]^c}{[A]^a[B]^b}$, where $[A]$, $[B]$, and $[C]$ are the molar concentrations of the reactants and products at equilibrium, and $a$, $b$, and $c$ are the stoichiometric coefficients.

Step2: Identify reactants and products and their coefficients

For the reaction $CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$, the reactants are $CO$ and $H_2$ with coefficients 1 and 2 respectively, and the product is $CH_3OH$ with coefficient 1.

Step3: Write the equilibrium - constant expression

$K_{eq}=\frac{[CH_3OH]}{[CO][H_2]^2}$

Answer:

$K_{eq}=\frac{[CH_3OH]}{[CO][H_2]^2}$ (the second option in the multiple - choice list)