consider the hydrate calcium chloride dihydrate: cacl2·2h2o. how many hydrogen atoms are in the compound…

Explanation:

Step1: Identify molar - masses of elements

The molar mass of Ca is approximately 40.08 g/mol, Cl is approximately 35.45 g/mol, H is approximately 1.01 g/mol, and O is approximately 16.00 g/mol.

Step2: Calculate molar - mass of $CaCl_2$

For $CaCl_2$, there is 1 Ca atom and 2 Cl atoms. So, $M_{CaCl_2}=40.08 + 2\times35.45=40.08 + 70.90 = 110.98\ g/mol$.

Step3: Calculate molar - mass of $2H_2O$

For $2H_2O$, there are 4 H atoms and 2 O atoms. So, $M_{2H_2O}=4\times1.01+2\times16.00 = 4.04+32.00 = 36.04\ g/mol$.

Step4: Calculate molar - mass of the hydrate

The molar - mass of $CaCl_2\cdot2H_2O$ is $M = M_{CaCl_2}+M_{2H_2O}=110.98 + 36.04=147.02\ g/mol$.

Answer:

147.02 g/mol