consider these intermediate chemical equations.\n2p (s) + 3cl₂ (g) → 2pcl₃ (l)\npcl₃ (l) + cl₂ (g) → pcl₅…

consider these intermediate chemical equations.\n2p (s) + 3cl₂ (g) → 2pcl₃ (l)\npcl₃ (l) + cl₂ (g) → pcl₅ (s)\nwhen you combine the intermediate chemical equations, which substance do you cancel out?\npcl₅\ncl₂\npcl₃\np

consider these intermediate chemical equations.\n2p (s) + 3cl₂ (g) → 2pcl₃ (l)\npcl₃ (l) + cl₂ (g) → pcl₅ (s)\nwhen you combine the intermediate chemical equations, which substance do you cancel out?\npcl₅\ncl₂\npcl₃\np

Answer

Brief Explanations:

In the first equation, $PCl_3$ is a product. In the second equation, $PCl_3$ is a reactant. When combining the equations, substances that appear as a product in one and a reactant in the other can be canceled out.

Answer:

$PCl_3$