consider the positions of barium (ba), sulfur (s), silicon (si), and calcium (ca) on the periodic table. the…

consider the positions of barium (ba), sulfur (s), silicon (si), and calcium (ca) on the periodic table. the atoms of which element require the least amount of energy to give up an electron when forming chemical bonds?\no barium\no sulfur\no silicon\no calcium

consider the positions of barium (ba), sulfur (s), silicon (si), and calcium (ca) on the periodic table. the atoms of which element require the least amount of energy to give up an electron when forming chemical bonds?\no barium\no sulfur\no silicon\no calcium

Answer

Explanation:

Step1: Recall ionization - energy trend

Ionization energy decreases down a group and increases across a period. The element that requires the least energy to give up an electron has the lowest first - ionization energy among the given elements.

Step2: Locate elements on periodic table

Barium (Ba) is in Group 2 and Period 6, sulfur (S) is in Group 16 and Period 3, silicon (Si) is in Group 14 and Period 3, and calcium (Ca) is in Group 2 and Period 4.

Step3: Compare ionization energies

Since ionization energy decreases down a group, Ba is below Ca in Group 2, so Ba has a lower ionization energy than Ca. Also, S and Si are non - metals in the p - block, and non - metals generally have higher ionization energies compared to metals in the s - block. So, Ba has the lowest ionization energy among the four elements.

Answer:

barium