consider the reactants written below: 3 mg(s) + 2 crcl3(aq)→ in the answer boxes below write the following…

consider the reactants written below: 3 mg(s) + 2 crcl3(aq)→ in the answer boxes below write the following: 1. the number of magnesium atoms present 2. the number of chromium atoms present 3. the number of chlorine atoms present

consider the reactants written below: 3 mg(s) + 2 crcl3(aq)→ in the answer boxes below write the following: 1. the number of magnesium atoms present 2. the number of chromium atoms present 3. the number of chlorine atoms present

Answer

Explanation:

Step1: Determine magnesium atoms

The coefficient of Mg is 3, so there are 3 magnesium atoms.

Step2: Determine chromium atoms

The coefficient of CrCl₃ is 2, and there is 1 Cr in each CrCl₃ unit. So the number of chromium atoms is 2×1 = 2.

Step3: Determine chlorine atoms

The coefficient of CrCl₃ is 2, and there are 3 Cl in each CrCl₃ unit. So the number of chlorine atoms is 2×3 = 6.

Answer:

  1. 3
  2. 2
  3. 6