consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced if 11.0 mol of al…

consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced if 11.0 mol of al are produced?\n8.25 mol\n11.0 mol\n14.7 mol\n16.5 mol

consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced if 11.0 mol of al are produced?\n8.25 mol\n11.0 mol\n14.7 mol\n16.5 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2Al_2O_3\rightarrow4Al + 3O_2$, the mole - ratio of $Al$ to $O_2$ is $4:3$.

Step2: Set up proportion

Let $x$ be the number of moles of $O_2$ produced. We have the proportion $\frac{4}{3}=\frac{11.0}{x}$.

Step3: Solve for $x$

Cross - multiply: $4x = 3\times11.0$. Then $x=\frac{3\times11.0}{4}=\frac{33.0}{4}=8.25$ mol.

Answer:

A. 8.25 mol