consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\nx = al₂(so₄)₃; y = h₂o\nx = al₂(so₄)₃…

consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\nx = al₂(so₄)₃; y = h₂o\nx = al₂(so₄)₃; y = h₂\nx = al₂(so₃)₃; y = h₂o\nx = al₂(so₃)₃; y = h₂

consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\nx = al₂(so₄)₃; y = h₂o\nx = al₂(so₄)₃; y = h₂\nx = al₂(so₃)₃; y = h₂o\nx = al₂(so₃)₃; y = h₂

Answer

Explanation:

Step1: Identify the reaction type

This is an acid - base reaction between aluminum hydroxide ($Al(OH)_3$) and sulfuric acid ($H_2SO_4$).

Step2: Write the general form of acid - base reaction

An acid - base reaction between a metal hydroxide and an acid produces a salt and water. The general form is $Metal\ hydroxide+Acid\rightarrow Salt + Water$.

Step3: Determine the salt and water

Aluminum hydroxide ($Al(OH)_3$) reacts with sulfuric acid ($H_2SO_4$). Aluminum ($Al^{3 + }$) combines with the sulfate ion ($SO_4^{2 - }$) to form the salt aluminum sulfate $Al_2(SO_4)_3$. The hydrogen from the acid and the hydroxide from the base combine to form water ($H_2O$). The balanced chemical equation is $2Al(OH)_3+3H_2SO_4\rightarrow Al_2(SO_4)_3 + 6H_2O$.

Answer:

A. $X = Al_2(SO_4)_3; Y = H_2O$