consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\no x = al₂(so₄)₃; y = h₂o\no x =…

consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\no x = al₂(so₄)₃; y = h₂o\no x = al₂(so₄)₃; y = h₂\no x = al₂(so₃)₃; y = h₂o\no x = al₂(so₃)₃; y = h₂

consider the reaction 2al(oh)₃ + 3h₂so₄ → x + 6y. what are x and y?\no x = al₂(so₄)₃; y = h₂o\no x = al₂(so₄)₃; y = h₂\no x = al₂(so₃)₃; y = h₂o\no x = al₂(so₃)₃; y = h₂

Answer

Explanation:

Step1: Analyze reactant elements

The reactants are $2Al(OH)_3$ and $3H_2SO_4$. The elements present are Al, O, H, S.

Step2: Recall acid - base reaction

This is an acid - base reaction (aluminum hydroxide is a base and sulfuric acid is an acid). The products of an acid - base reaction are a salt and water.

Step3: Determine salt formation

Aluminum from $Al(OH)_3$ and sulfate from $H_2SO_4$ form the salt $Al_2(SO_4)_3$.

Step4: Determine water formation

The hydrogen from the acid and the hydroxide from the base combine to form water $H_2O$. The balanced reaction is $2Al(OH)_3 + 3H_2SO_4=Al_2(SO_4)_3 + 6H_2O$.

Answer:

A. $X = Al_2(SO_4)_3; Y = H_2O$