consider the reaction below.\n2c6h14 + 19o2 → 12co2 + 14h2o\nhow many moles of hexane (c6h14) must burn to…

consider the reaction below.\n2c6h14 + 19o2 → 12co2 + 14h2o\nhow many moles of hexane (c6h14) must burn to form 18.4 mol of carbon dioxide?\no 1.53 mol\no 3.07 mol\no 110. mol\no 175. mol

consider the reaction below.\n2c6h14 + 19o2 → 12co2 + 14h2o\nhow many moles of hexane (c6h14) must burn to form 18.4 mol of carbon dioxide?\no 1.53 mol\no 3.07 mol\no 110. mol\no 175. mol

Answer

Answer:

A. 3.07 mol

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2C_6H_{14}+19O_2\rightarrow12CO_2 + 14H_2O$, the mole - ratio of $C_6H_{14}$ to $CO_2$ is $\frac{n_{C_6H_{14}}}{n_{CO_2}}=\frac{2}{12}=\frac{1}{6}$.

Step2: Calculate moles of hexane

We know $n_{CO_2}=18.4$ mol. Using the mole - ratio, $n_{C_6H_{14}}=\frac{1}{6}\times n_{CO_2}$. Substituting the value of $n_{CO_2}$, we get $n_{C_6H_{14}}=\frac{1}{6}\times18.4$ mol $\approx3.07$ mol.