consider the reaction below.\n2h₂o → 2h₂ + o₂\nhow many moles of hydrogen are produced when 6.28 mol of…

consider the reaction below.\n2h₂o → 2h₂ + o₂\nhow many moles of hydrogen are produced when 6.28 mol of oxygen form?\no 3.14 mol\no 6.28 mol\no 12.6 mol\no 25.2 mol

consider the reaction below.\n2h₂o → 2h₂ + o₂\nhow many moles of hydrogen are produced when 6.28 mol of oxygen form?\no 3.14 mol\no 6.28 mol\no 12.6 mol\no 25.2 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2H_2O\rightarrow2H_2 + O_2$, the mole - ratio of $H_2$ to $O_2$ is $2:1$.

Step2: Calculate moles of hydrogen

Let $n_{H_2}$ be the moles of hydrogen and $n_{O_2}$ be the moles of oxygen. We know that $\frac{n_{H_2}}{n_{O_2}}=\frac{2}{1}$. Given $n_{O_2} = 6.28$ mol. Then $n_{H_2}=2\times n_{O_2}$. Substituting the value of $n_{O_2}$, we get $n_{H_2}=2\times6.28$ mol. $n_{H_2}=12.56\approx12.6$ mol

Answer:

12.6 mol