consider the reaction below. 2i⁻(aq)+cl₂(g)→2cl⁻(aq)+i₂(aq) which half - reaction correctly describes the…

consider the reaction below. 2i⁻(aq)+cl₂(g)→2cl⁻(aq)+i₂(aq) which half - reaction correctly describes the reduction that is taking place? cl₂(g)+2e⁻→2cl⁻(aq) cl₂(g)+e⁻→2cl⁻(aq) 2i⁻(aq)→i₂(aq)+2e⁻ 2i⁻(aq)→i₂(aq)+e⁻

consider the reaction below. 2i⁻(aq)+cl₂(g)→2cl⁻(aq)+i₂(aq) which half - reaction correctly describes the reduction that is taking place? cl₂(g)+2e⁻→2cl⁻(aq) cl₂(g)+e⁻→2cl⁻(aq) 2i⁻(aq)→i₂(aq)+2e⁻ 2i⁻(aq)→i₂(aq)+e⁻

Answer

Explanation:

Step1: Recall reduction concept

Reduction is gain of electrons.

Step2: Analyze reactants and products

In the overall reaction $2I^-(aq)+Cl_2(g)\longrightarrow 2Cl^-(aq)+I_2(aq)$, chlorine in $Cl_2$ goes from 0 oxidation - state to - 1 in $Cl^-$. It gains electrons.

Step3: Write correct half - reaction

The half - reaction for the reduction of $Cl_2$ is $Cl_2(g)+2e^-\longrightarrow 2Cl^-(aq)$ as it shows $Cl_2$ gaining 2 electrons to form 2 $Cl^-$ ions.

Answer:

$Cl_2(g)+2e^-\longrightarrow 2Cl^-(aq)$