consider the reaction below.\n2k + br₂ → 2k⁺ + 2br⁻\nwhat is being reduced?\nonly k\nonly br₂\nboth k and…

consider the reaction below.\n2k + br₂ → 2k⁺ + 2br⁻\nwhat is being reduced?\nonly k\nonly br₂\nboth k and br₂\nneither k nor br₂

consider the reaction below.\n2k + br₂ → 2k⁺ + 2br⁻\nwhat is being reduced?\nonly k\nonly br₂\nboth k and br₂\nneither k nor br₂

Answer

Answer:

B. only $Br_2$

Explanation:

Step1: Determine oxidation states

In $2K + Br_2\rightarrow2K^+ + 2Br^-$, the oxidation state of $K$ changes from 0 in elemental $K$ to +1 in $K^+$. The oxidation state of $Br$ changes from 0 in elemental $Br_2$ to - 1 in $Br^-$.

Step2: Define oxidation and reduction

Oxidation is the increase in oxidation state. Reduction is the decrease in oxidation state. Since the oxidation state of $Br$ decreases from 0 to -1, $Br_2$ is being reduced.