consider this reaction.\n2so₂(g) + o₂(g)→2so₃(g)\nwhat volume of oxygen gas, in milliliters, is required to…

Explanation:

Step1: Calculate moles of SO₂

The molar mass of SO₂ is $M_{SO_2}=32 + 2\times16=64\ g/mol$. The number of moles of SO₂, $n_{SO_2}=\frac{m}{M}=\frac{0.640\ g}{64\ g/mol}=0.01\ mol$.

Step2: Determine moles of O₂ from stoichiometry

From the balanced equation $2SO_2(g)+O_2(g)\rightarrow2SO_3(g)$, the mole - ratio of $SO_2$ to $O_2$ is 2:1. So, $n_{O_2}=\frac{1}{2}n_{SO_2}=\frac{1}{2}\times0.01\ mol = 0.005\ mol$.

Step3: Calculate volume of O₂ at STP

At STP (Standard Temperature and Pressure, $T = 273\ K$ and $P=1\ atm$), the molar volume of a gas is $V_m = 22.4\ L/mol$. The volume of $O_2$, $V_{O_2}=n_{O_2}\times V_m=0.005\ mol\times22.4\ L/mol = 0.112\ L$. Convert to mL: $V_{O_2}=0.112\ L\times1000\ mL/L = 112\ mL$.

Answer:

112 mL