consider the reaction when aqueous solutions of lead(ii) nitrate and nickel(ii) chloride are combined. the…

consider the reaction when aqueous solutions of lead(ii) nitrate and nickel(ii) chloride are combined. the net ionic equation for this reaction is: (be sure to specify states such as (aq) or (s). if a box is not needed leave it blank. if no reaction occurs leave all boxes blank and click on \submit\).

consider the reaction when aqueous solutions of lead(ii) nitrate and nickel(ii) chloride are combined. the net ionic equation for this reaction is: (be sure to specify states such as (aq) or (s). if a box is not needed leave it blank. if no reaction occurs leave all boxes blank and click on \submit\).

Answer

Explanation:

Step1: Write the molecular equation

Lead(II) nitrate is $Pb(NO_3)_2(aq)$ and nickel(II) chloride is $NiCl_2(aq)$. They react via a double - displacement reaction. The products are lead(II) chloride $PbCl_2(s)$ (since it is insoluble) and nickel(II) nitrate $Ni(NO_3)_2(aq)$. The molecular equation is $Pb(NO_3)_2(aq)+NiCl_2(aq)\rightarrow PbCl_2(s)+Ni(NO_3)_2(aq)$.

Step2: Write the complete ionic equation

The complete ionic equation shows all the ions in solution. $Pb^{2 +}(aq)+2NO_3^{-}(aq)+Ni^{2 +}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)+Ni^{2 +}(aq)+2NO_3^{-}(aq)$.

Step3: Write the net ionic equation

Cancel out the spectator ions ($Ni^{2+}$ and $NO_3^{-}$). The net ionic equation is $Pb^{2 +}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)$.

Answer:

$Pb^{2 +}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)$