consider the reaction.\nh₂o(g)+cl₂o(g)⇌2hclo(g)\nat equilibrium, the concentrations of the different species…

consider the reaction.\nh₂o(g)+cl₂o(g)⇌2hclo(g)\nat equilibrium, the concentrations of the different species are as follows.\nh₂o=0.077 m\ncl₂o=0.077 m\nhclo=0.023 m\nwhat is the equilibrium constant for the reaction at this temperature?\n0.089\n0.26\n3.9\n11

consider the reaction.\nh₂o(g)+cl₂o(g)⇌2hclo(g)\nat equilibrium, the concentrations of the different species are as follows.\nh₂o=0.077 m\ncl₂o=0.077 m\nhclo=0.023 m\nwhat is the equilibrium constant for the reaction at this temperature?\n0.089\n0.26\n3.9\n11

Answer

Answer:

0.089

Explanation:

Step1: Write equilibrium - constant expression

For the reaction $H_2O(g)+Cl_2O(g)\rightleftharpoons 2HClO(g)$, the equilibrium - constant expression $K_c=\frac{[HClO]^2}{[H_2O][Cl_2O]}$.

Step2: Substitute the given concentrations

Substitute $[H_2O]=0.077\ M$, $[Cl_2O]=0.077\ M$, and $[HClO]=0.023\ M$ into the expression: $K_c=\frac{(0.023)^2}{0.077\times0.077}$.

Step3: Calculate the value of $K_c$

$K_c=\frac{0.000529}{0.005929}\approx0.089$.