consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for…

consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\n○ h⁺+cl⁻→hcl\n○ na⁺+cl⁻→nacl\n○ na⁺+c₂h₃o₂⁻→nac₂h₃o₂\n○ c₂h₃o₂⁻(aq)+h⁺→hc₂h₃o₂

consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\n○ h⁺+cl⁻→hcl\n○ na⁺+cl⁻→nacl\n○ na⁺+c₂h₃o₂⁻→nac₂h₃o₂\n○ c₂h₃o₂⁻(aq)+h⁺→hc₂h₃o₂

Answer

Explanation:

Step1: Identify spectator ions

Spectator ions are ions that appear on both sides of the complete - ionic equation and do not participate in the actual chemical change. In the given equation $Na^{+}+C_{2}H_{3}O_{2}^{-}(aq)+H^{+}+Cl^{-}\longrightarrow Na^{+}+Cl^{-}+HC_{2}H_{3}O_{2}$, $Na^{+}$ and $Cl^{-}$ are spectator ions.

Step2: Write the net - ionic equation

Remove the spectator ions from the complete - ionic equation. The net - ionic equation is obtained by eliminating $Na^{+}$ and $Cl^{-}$ from both sides of the equation. So the net - ionic equation is $C_{2}H_{3}O_{2}^{-}(aq)+H^{+}\longrightarrow HC_{2}H_{3}O_{2}$.

Answer:

D. $C_{2}H_{3}O_{2}^{-}(aq)+H^{+}\longrightarrow HC_{2}H_{3}O_{2}$