consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for…

consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\no h⁺+cl⁻→hcl\no na⁺+cl⁻→nacl\no na⁺+c₂h₃o₂⁻→nac₂h₃o₂\no c₂h₃o₂⁻(aq)+h⁺→hc₂h₃o₂

consider the reaction below.\nna⁺+c₂h₃o₂⁻(aq)+h⁺+cl⁻→na⁺+cl⁻+hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\no h⁺+cl⁻→hcl\no na⁺+cl⁻→nacl\no na⁺+c₂h₃o₂⁻→nac₂h₃o₂\no c₂h₃o₂⁻(aq)+h⁺→hc₂h₃o₂

Answer

Explanation:

Step1: Identify spectator ions

Spectator ions are those that appear on both sides of the total ionic equation. Here, $Na^+$ and $Cl^-$ are present on both sides.

Step2: Write net - ionic equation

Remove the spectator ions from the total ionic equation. The remaining species form the net - ionic equation. So, $C_2H_3O_2^-(aq)+H^+\longrightarrow HC_2H_3O_2$.

Answer:

D. $C_2H_3O_2^-(aq)+H^+\longrightarrow HC_2H_3O_2$