consider the reaction below.\nzn(s)+cu²⁺(aq)→zn²⁺(aq)+cu(s)\nwhich half - reaction correctly describes the…

consider the reaction below.\nzn(s)+cu²⁺(aq)→zn²⁺(aq)+cu(s)\nwhich half - reaction correctly describes the oxidation that is taking place?\no zn(s)→zn²⁺(aq)+e⁻\no zn(s)→zn²⁺(aq)+2e⁻\no cu²⁺(aq)+2e⁻→cu(s)\no cu²⁺(aq)+e⁻→cu(s)

consider the reaction below.\nzn(s)+cu²⁺(aq)→zn²⁺(aq)+cu(s)\nwhich half - reaction correctly describes the oxidation that is taking place?\no zn(s)→zn²⁺(aq)+e⁻\no zn(s)→zn²⁺(aq)+2e⁻\no cu²⁺(aq)+2e⁻→cu(s)\no cu²⁺(aq)+e⁻→cu(s)

Answer

Explanation:

Step1: Understand oxidation

Oxidation is the loss of electrons.

Step2: Analyze the reaction

In the reaction $Zn(s)+Cu^{2 +}(aq)\longrightarrow Zn^{2 +}(aq)+Cu(s)$, zinc goes from an oxidation state of 0 in $Zn(s)$ to + 2 in $Zn^{2+}(aq)$.

Step3: Write the oxidation half - reaction

Zinc loses 2 electrons to form zinc ion. The half - reaction is $Zn(s)\longrightarrow Zn^{2+}(aq)+2e^-$.

Answer:

$Zn(s)\longrightarrow Zn^{2+}(aq)+2e^-$