consider the total ionic equation below.\nba²⁺ + 2no₃⁻ + 2na⁺ + co₃²⁻ → baco₃ + 2na⁺ + 2no₃⁻\nwhich is the…

consider the total ionic equation below.\nba²⁺ + 2no₃⁻ + 2na⁺ + co₃²⁻ → baco₃ + 2na⁺ + 2no₃⁻\nwhich is the net ionic equation for the reaction?\n○ ba²⁺ + co₃²⁻ → baco₃\n○ 2na⁺ + co₃²⁻ → na₂co₃\n○ no₃⁻ + na⁺ → nano₃\n○ ba²⁺ + 2no₃⁻ → ba(no₃)₂

consider the total ionic equation below.\nba²⁺ + 2no₃⁻ + 2na⁺ + co₃²⁻ → baco₃ + 2na⁺ + 2no₃⁻\nwhich is the net ionic equation for the reaction?\n○ ba²⁺ + co₃²⁻ → baco₃\n○ 2na⁺ + co₃²⁻ → na₂co₃\n○ no₃⁻ + na⁺ → nano₃\n○ ba²⁺ + 2no₃⁻ → ba(no₃)₂

Answer

Explanation:

Step1: Identify spectator ions

Spectator ions are those that appear on both sides of the total - ionic equation. Here, $2Na^{+}$ and $2NO_{3}^{-}$ are spectator ions.

Step2: Write the net - ionic equation

Remove the spectator ions from the total - ionic equation. The remaining ions and the product form the net - ionic equation. The total ionic equation is $Ba^{2 +}+2NO_{3}^{-}+2Na^{+}+CO_{3}^{2 -}\longrightarrow BaCO_{3}+2Na^{+}+2NO_{3}^{-}$. After removing $2Na^{+}$ and $2NO_{3}^{-}$ from both sides, we get $Ba^{2 +}+CO_{3}^{2 -}\longrightarrow BaCO_{3}$.

Answer:

$Ba^{2 +}+CO_{3}^{2 -}\longrightarrow BaCO_{3}$