consider the unbalanced equation for the oxidation of aluminum.\n_al + _o₂ → _al₂o₃\nwhich sequence of…

consider the unbalanced equation for the oxidation of aluminum.\n_al + _o₂ → _al₂o₃\nwhich sequence of coefficients should be placed in the blanks to balance this equation?\no 2,3,1\no 1,3,2\no 4,3,2\no 3,2,3

consider the unbalanced equation for the oxidation of aluminum.\n_al + _o₂ → _al₂o₃\nwhich sequence of coefficients should be placed in the blanks to balance this equation?\no 2,3,1\no 1,3,2\no 4,3,2\no 3,2,3

Answer

Explanation:

Step1: Balance oxygen atoms

On the right - hand side, there are 3 oxygen atoms in $Al_2O_3$. On the left - hand side, oxygen is in $O_2$. To balance oxygen, find the least common multiple of 2 and 3. The least common multiple of 2 and 3 is 6. So, we need 3 $O_2$ molecules to get 6 oxygen atoms on the left and 2 $Al_2O_3$ molecules to get 6 oxygen atoms on the right. The equation becomes $Al+3O_2\rightarrow2Al_2O_3$.

Step2: Balance aluminum atoms

Now, on the right - hand side, there are 4 aluminum atoms in 2 $Al_2O_3$. So, we need 4 aluminum atoms on the left - hand side. The balanced equation is $4Al + 3O_2\rightarrow2Al_2O_3$.

Answer:

4, 3, 2