copper(i) chloride\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this…

copper(i) chloride\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\nsubmit request answer\npart b\niron(ii) iodate\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\nsubmit request answer

copper(i) chloride\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\nsubmit request answer\npart b\niron(ii) iodate\nexpress your answer as a chemical formula.\na chemical reaction does not occur for this question.\nsubmit request answer

Answer

Explanation:

Step1: Determine copper(I) ion and chloride ion

Copper(I) has a +1 charge ($Cu^+$), chloride ion is $Cl^-$ with a - 1 charge.

Step2: Write the chemical formula

To form a neutral compound, the ratio of ions is 1:1. So the formula is $CuCl$.

Step3: Determine iron(II) ion and iodate ion

Iron(II) has a +2 charge ($Fe^{2+}$), iodate ion is $IO_3^-$ with a - 1 charge.

Step4: Write the chemical formula

To balance the charges, 2 iodate ions are needed for 1 iron(II) ion. So the formula is $Fe(IO_3)_2$.

Answer:

Part A: $CuCl$ Part B: $Fe(IO_3)_2$