copper reacts with sulfur to form copper (i) sulfide, according to the balanced equation below. 2cu + s →…

copper reacts with sulfur to form copper (i) sulfide, according to the balanced equation below. 2cu + s → cu₂s. given that there are 40.2 g cu and 14.1 g s, complete the steps below to determine the limiting and excess reactants in the last question. how many moles are in 40.2 g cu? mol cu. how many moles are in 14.1 g s? mol s. done

copper reacts with sulfur to form copper (i) sulfide, according to the balanced equation below. 2cu + s → cu₂s. given that there are 40.2 g cu and 14.1 g s, complete the steps below to determine the limiting and excess reactants in the last question. how many moles are in 40.2 g cu? mol cu. how many moles are in 14.1 g s? mol s. done

Answer

Explanation:

Step1: Recall molar - mass formula

The formula to calculate the number of moles $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass. The molar mass of $Cu$ is $M_{Cu}=63.55\ g/mol$ and the molar mass of $S$ is $M_{S}=32.07\ g/mol$.

Step2: Calculate moles of Cu

Using the formula $n=\frac{m}{M}$, for $m = 40.2\ g$ of $Cu$, we have $n_{Cu}=\frac{40.2\ g}{63.55\ g/mol}\approx0.633\ mol$.

Step3: Calculate moles of S

Using the formula $n=\frac{m}{M}$, for $m = 14.1\ g$ of $S$, we have $n_{S}=\frac{14.1\ g}{32.07\ g/mol}\approx0.440\ mol$.

Answer:

0.633 mol Cu 0.440 mol S