which is the correctly balanced chemical equation for the reaction of koh and h₂so₄?\no koh→h₂so₄→k⁺+so₄²⁻\no…

which is the correctly balanced chemical equation for the reaction of koh and h₂so₄?\no koh→h₂so₄→k⁺+so₄²⁻\no 2koh+h₂so₄→k₂so₄\no 2koh+h₂so₄→k₂so₄+2h₂o\no koh→h₂so₄→k₂so₄→h₂o

which is the correctly balanced chemical equation for the reaction of koh and h₂so₄?\no koh→h₂so₄→k⁺+so₄²⁻\no 2koh+h₂so₄→k₂so₄\no 2koh+h₂so₄→k₂so₄+2h₂o\no koh→h₂so₄→k₂so₄→h₂o

Answer

Answer:

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

Explanation:

Step1: Analyze reactants and products

Potassium hydroxide (KOH) reacts with sulfuric acid (H₂SO₄) to form potassium sulfate (K₂SO₄) and water (H₂O).

Step2: Balance potassium (K) atoms

There is 1 K in KOH and 2 K in K₂SO₄. So, put a coefficient of 2 in front of KOH: 2KOH + H₂SO₄ → K₂SO₄ + H₂O.

Step3: Balance hydrogen (H) and oxygen (O) atoms

On the left - hand side, we have 2KOH (2 H from 2KOH and 2 H from H₂SO₄, total 4 H) and on the right - hand side we have 2 H in H₂O. Also, for oxygen, on the left we have 2KOH (2 O) and H₂SO₄ (4 O), total 6 O, and on the right we have K₂SO₄ (4 O) and H₂O (1 O). By putting a coefficient of 2 in front of H₂O, we get 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O which balances all the atoms.