counting atoms practice\nidentify the number of atoms for each element in the following compounds.\n1)…

counting atoms practice\nidentify the number of atoms for each element in the following compounds.\n1) mg(oh)₂ mg = o = h =\n2) caco₃ ca = c = o =\n3) ba₃(po₄)₂ ba = p = o =\n4) fe(cn)₃ fe = c = n =\n5) ccl₄ c = cl =\n6) na₂so₄ na = s = o =\n7) srf₂ sr = f = o =\n8) nh₄no₃ n = h = o =\n9) ch₃cooh c = h = o =\n10) cu(no₃)₂ cu = n =

counting atoms practice\nidentify the number of atoms for each element in the following compounds.\n1) mg(oh)₂ mg = o = h =\n2) caco₃ ca = c = o =\n3) ba₃(po₄)₂ ba = p = o =\n4) fe(cn)₃ fe = c = n =\n5) ccl₄ c = cl =\n6) na₂so₄ na = s = o =\n7) srf₂ sr = f = o =\n8) nh₄no₃ n = h = o =\n9) ch₃cooh c = h = o =\n10) cu(no₃)₂ cu = n =

Answer

Explanation:

Step1: Analyze $Mg(OH)_2$

$Mg$ has 1 atom, $O$ has $1\times2 = 2$ atoms, $H$ has $1\times2 = 2$ atoms.

Step2: Analyze $CaCO_3$

$Ca$ has 1 atom, $C$ has 1 atom, $O$ has 3 atoms.

Step3: Analyze $Ba_3(PO_4)_2$

$Ba$ has 3 atoms, $P$ has $1\times2=2$ atoms, $O$ has $4\times2 = 8$ atoms.

Step4: Analyze $Fe(CN)_3$

$Fe$ has 1 atom, $C$ has $1\times3 = 3$ atoms, $N$ has $1\times3 = 3$ atoms.

Step5: Analyze $CCl_4$

$C$ has 1 atom, $Cl$ has 4 atoms.

Step6: Analyze $Na_2SO_4$

$Na$ has 2 atoms, $S$ has 1 atom, $O$ has 4 atoms.

Step7: Analyze $SrF_2$

$Sr$ has 1 atom, $F$ has 2 atoms, $O$ has 0 atoms.

Step8: Analyze $NH_4NO_3$

$N$ has $1 + 1=2$ atoms, $H$ has $4$ atoms, $O$ has 3 atoms.

Step9: Analyze $CH_3COOH$

$C$ has $1+1 = 2$ atoms, $H$ has $3 + 1=4$ atoms, $O$ has 2 atoms.

Step10: Analyze $Cu(NO_3)_2$

$Cu$ has 1 atom, $N$ has $1\times2 = 2$ atoms, $O$ has $3\times2 = 6$ atoms.

Answer:

Compound $Mg$ $O$ $H$ $Ca$ $C$ $Ba$ $P$ $Fe$ $N$ $Cl$ $Na$ $S$ $Sr$ $F$ $Cu$
$Mg(OH)_2$ 1 2 2
$CaCO_3$ 3 1 1
$Ba_3(PO_4)_2$ 8 3 2
$Fe(CN)_3$ 3 1 3
$CCl_4$ 1 4
$Na_2SO_4$ 4 2 1
$SrF_2$ 0 1 2
$NH_4NO_3$ 3 4 2
$CH_3COOH$ 2 4 2
$Cu(NO_3)_2$ 6 2 1