decide whether each pair of elements in the table below will form an ionic compound. if they will, write the…
decide whether each pair of elements in the table below will form an ionic compound. if they will, write the empirical formula and name of the ionic compound formed in the spaces provided.\n| element #1 | element #2 | forms ionic compound? | empirical formula of ionic compound | name of ionic compound |\n|--|--|--|--|--|\n| sulfur | strontium | yes no | | |\n| calcium | chlorine | yes no | | |\n| oxygen | rubidium | yes no | | |\n| barium | lithium | yes no | | |
Answer
Explanation:
Step1: Recall ionic - compound formation rule
Ionic compounds form between a metal and a non - metal.
Step2: Analyze sulfur and strontium pair
Sulfur is a non - metal and strontium is a metal. They form an ionic compound. Strontium forms a $Sr^{2 + }$ ion and sulfur forms a $S^{2 - }$ ion. The empirical formula is $SrS$ and the name is strontium sulfide.
Step3: Analyze calcium and chlorine pair
Calcium is a metal and chlorine is a non - metal. Calcium forms a $Ca^{2+}$ ion and chlorine forms a $Cl^{-}$ ion. To balance the charges, the empirical formula is $CaCl_{2}$ and the name is calcium chloride.
Step4: Analyze oxygen and rubidium pair
Oxygen is a non - metal and rubidium is a metal. Rubidium forms a $Rb^{+}$ ion and oxygen forms an $O^{2 - }$ ion. The empirical formula is $Rb_{2}O$ and the name is rubidium oxide.
Step5: Analyze barium and lithium pair
Both barium and lithium are metals. They do not form an ionic compound.
Answer:
| element #1 | element #2 | Forms ionic compound? | empirical formula of ionic compound | name of ionic compound |
|---|---|---|---|---|
| sulfur | strontium | yes | $SrS$ | strontium sulfide |
| calcium | chlorine | yes | $CaCl_{2}$ | calcium chloride |
| oxygen | rubidium | yes | $Rb_{2}O$ | rubidium oxide |
| barium | lithium | no |