decide whether these proposed lewis structures are reasonable.\nproposed lewis structure is the proposed…

decide whether these proposed lewis structures are reasonable.\nproposed lewis structure is the proposed lewis structure reasonable?\nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \n* if two or more atoms of the same element dont satisfy the octet rule, just enter the chemical symbol as many times as necessary. for example, if two oxygen atoms dont satisfy the octet rule, enter \o,o\.

decide whether these proposed lewis structures are reasonable.\nproposed lewis structure is the proposed lewis structure reasonable?\nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \nyes.\nno, it has the wrong number of valence electrons.\nthe correct number is: \nno, it has the right number of valence electrons but doesnt satisfy the octet rule.\nthe symbols of the problem atoms are: * \n* if two or more atoms of the same element dont satisfy the octet rule, just enter the chemical symbol as many times as necessary. for example, if two oxygen atoms dont satisfy the octet rule, enter \o,o\.

Answer

Explanation:

Step1: Calculate valence - electrons for $H_2C_2$

Hydrogen ($H$) has 1 valence electron and carbon ($C$) has 4 valence electrons. For $H_2C_2$, the number of valence electrons is $2\times1 + 2\times4=10$. In the given Lewis - structure of $H - C - C - H$, each $C$ has only 6 electrons around it (4 bonding electrons and 2 non - bonding electrons), so it doesn't satisfy the octet rule. The problem atoms are $C,C$.

Step2: Calculate valence - electrons for $[OC≡H]^+$

Oxygen ($O$) has 6 valence electrons, carbon ($C$) has 4 valence electrons, and hydrogen ($H$) has 1 valence electron. The total number of valence electrons for $OC≡H$ without the charge is $6 + 4+1 = 11$. With a + 1 charge, the number of valence electrons is $11-1 = 10$. In the given structure, $O$ has 10 electrons around it (6 non - bonding electrons and 4 bonding electrons), which violates the octet rule. The problem atom is $O$.

Step3: Calculate valence - electrons for $[C≡N]^-$

Carbon ($C$) has 4 valence electrons and nitrogen ($N$) has 5 valence electrons. With a - 1 charge, the number of valence electrons is $4 + 5+1=10$. In the given structure, both $C$ and $N$ have 8 electrons around them (3 bonding pairs and 1 non - bonding pair), so the Lewis structure is reasonable.

Answer:

  1. No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: $C,C$
  2. No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: $O$
  3. Yes.