the density of hydrogen is approximately 9×10⁻⁵ $\frac{g}{cm^{3}}$, while the density of helium is…

the density of hydrogen is approximately 9×10⁻⁵ $\frac{g}{cm^{3}}$, while the density of helium is approximately 2×10⁻⁴ $\frac{g}{cm^{3}}$. which of the following is true?\n\na. the density of helium is approximately 2 times the density of hydrogen\n\nb. the density of hydrogen is approximately 2 times the density of helium\n\nc. the density of hydrogen is approximately 20 times the density of helium\n\nd. the density of helium is approximately 20 times the density of hydrogen

the density of hydrogen is approximately 9×10⁻⁵ $\frac{g}{cm^{3}}$, while the density of helium is approximately 2×10⁻⁴ $\frac{g}{cm^{3}}$. which of the following is true?\n\na. the density of helium is approximately 2 times the density of hydrogen\n\nb. the density of hydrogen is approximately 2 times the density of helium\n\nc. the density of hydrogen is approximately 20 times the density of helium\n\nd. the density of helium is approximately 20 times the density of hydrogen

Answer

Explanation:

Step1: Set up the ratio

Let $\rho_{H}$ be the density of hydrogen and $\rho_{He}$ be the density of helium. $\rho_{H}=9\times 10^{-5}\frac{g}{cm^{3}}$ and $\rho_{He}=2\times 10^{-4}\frac{g}{cm^{3}}$. We want to find $\frac{\rho_{He}}{\rho_{H}}$.

Step2: Calculate the ratio

$\frac{\rho_{He}}{\rho_{H}}=\frac{2\times 10^{-4}}{9\times 10^{-5}}=\frac{2}{9}\times10^{\left(- 4-\left(-5\right)\right)}=\frac{2}{9}\times10^{1}\approx\frac{20}{9}\approx2$.

Answer:

A. The density of helium is approximately 2 times the density of hydrogen