2. the density of a liquid is 0.739 g/ml. what is the mass of 125 ml of the sample? 3. a graduated cylinder…

2. the density of a liquid is 0.739 g/ml. what is the mass of 125 ml of the sample? 3. a graduated cylinder was filled with 25.0 ml of water. a solid object was immersed in the cylinder, raising the water level to 32.9 ml. the solid has a mass of 69.2 grams. what is the density of the object? the density of carbon tetrachloride is 1.59 g/ml. calculate the volume of 26.4 grams of the liquid.

2. the density of a liquid is 0.739 g/ml. what is the mass of 125 ml of the sample? 3. a graduated cylinder was filled with 25.0 ml of water. a solid object was immersed in the cylinder, raising the water level to 32.9 ml. the solid has a mass of 69.2 grams. what is the density of the object? the density of carbon tetrachloride is 1.59 g/ml. calculate the volume of 26.4 grams of the liquid.

Answer

2.

Explicación:

Paso 1: Identificar la fórmula

La fórmula de la densidad es $\rho=\frac{m}{V}$, donde $\rho$ es la densidad, $m$ es la masa y $V$ es el volumen. Re - arreglamos para encontrar la masa $m = \rho\times V$.

Paso 2: Sustituir valores

Dado que $\rho = 0.739\ g/ml$ y $V = 125\ ml$, entonces $m=0.739\ g/ml\times125\ ml$. $m = 92.375\ g$

Respuesta:

$92.375\ g$

3.

Explicación:

Paso 1: Calcular el volumen del objeto

El volumen del objeto es igual al cambio en el nivel del agua en el cilindro graduado. $V=V_{final}-V_{inicial}$. $V = 32.9\ ml - 25.0\ ml=7.9\ ml$

Paso 2: Calcular la densidad

Usando la fórmula $\rho=\frac{m}{V}$, con $m = 69.2\ g$ y $V = 7.9\ ml$. $\rho=\frac{69.2\ g}{7.9\ ml}\approx8.76\ g/ml$

Respuesta:

$8.76\ g/ml$

4.

Explicación:

Paso 1: Re - arreglar la fórmula de densidad

A partir de $\rho=\frac{m}{V}$, re - arreglamos para encontrar el volumen $V=\frac{m}{\rho}$.

Paso 2: Sustituir valores

Dado que $m = 26.4\ g$ y $\rho = 1.59\ g/ml$, entonces $V=\frac{26.4\ g}{1.59\ g/ml}\approx16.6\ ml$

Respuesta:

$16.6\ ml$