determine the molar mass of mn(clo3)4. molar mass: g/mol

Answer

Explanation:

Step1: Identify atomic masses

The atomic mass of Mn (manganese) is approximately 54.94 g/mol, Cl (chlorine) is approximately 35.45 g/mol, and O (oxygen) is approximately 16.00 g/mol.

Step2: Calculate mass from sub - scripts

In $Mn(ClO_3)_4$, there is 1 Mn atom, 4 Cl atoms, and 12 O atoms. The contribution of Mn to the molar mass is $1\times54.94$ g/mol = 54.94 g/mol. The contribution of Cl is $4\times35.45$ g/mol = 141.8 g/mol. The contribution of O is $12\times16.00$ g/mol = 192 g/mol.

Step3: Sum up the masses

The molar mass of $Mn(ClO_3)_4$ is $54.94 + 141.8+192$ g/mol = 388.74 g/mol.

Answer:

388.74 g/mol